3x^2=x/12

Solution for 3x^2=x/12 equation:

3x^2=x/12

We move all terms to the left:

3x^2-(x/12)=0

We add all the numbers together, and all the variables

3x^2-(+x/12)=0

We get rid of parentheses

3x^2-x/12=0

We multiply all the terms by the denominator


3x^2*12-x=0

We add all the numbers together, and all the variables

3x^2*12-1x=0

Wy multiply elements

36x^2-1x=0

a = 36; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·36·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*36}=\frac{2}{72}
=1/36
$